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Find the coordinates of point p along the directed line segment ab so that ap to pb is the given ratio: a(3,1), b(8, -2); 2 to 3

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Final answer:

The coordinates of point p along the directed line segment ab so that ap to pb is the given ratio are (5, -0.2).

Step-by-step explanation:

To find the coordinates of point P along the directed line segment from A(3,1) to B(8, -2) with the ratio of AP to PB being 2 to 3, we can use the section formula. This formula gives us the coordinates of a point that divides a segment into a certain ratio. The section formula for a ratio m:n is given by:
P(x, y) = ((mx2 + nx1) / (m + n), (my2 + ny1) / (m + n))

For the points A and B with given coordinates and the ratio 2:3, we substitute into the formula as follows:

  • x1 = 3
  • y1 = 1
  • x2 = 8
  • y2 = -2
  • m = 2
  • n = 3

Substitute these values into the section formula:
P(x, y) = ((2*8 + 3*3) / (2 + 3), (2*-2 + 3*1) / (2 + 3))
P(x, y) = ((16 + 9) / 5, (-4 + 3) / 5)
P(x, y) = (25 / 5, -1 / 5)
P(x, y) = (5, -0.2)

Therefore, the coordinates of point P are (5, -0.2).

User Mxcl
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