Question

A single-coil loop of radius r=8.60 mm, shown below, is formed in the middle of an infinitely long, thin, insulated straight wire carrying the current i=33.0 mA. What is the magnitude of the magnetic field at the center of the loop?

Answer 1

The magnetic field at the center of the single-coil loop is 1.52 × 10⁻⁶ T.

Step-by-step explanation:

The magnetic field at the center of a single-coil loop carrying a current can be calculated using the formula B = μ₀i / (2πr), where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), i is the current, and r is the radius of the loop.

Plugging in the values given in the question: i = 33.0 mA = 33.0 × 10⁻³ A, r = 8.60 mm = 8.60 × 10⁻³ m,

B = (4π × 10⁻⁷ T·m/A) × (33.0 × 10⁻³ A) / (2π × 8.60 × 10⁻³ m) = 1.52 × 10⁻⁶ T.