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A 1,917.50 mg nugget of lead released 26.78 j of heat. what was the final temperature of the lead if the initial temperature was 25.40℃? was this an endothermic or exothermic process?

User Mnsalim
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Final answer:

To calculate the final temperature of a lead nugget after heat release, we use the formula Q = mcΔT. Assuming the specific heat capacity of lead is 0.128 J/g°C, we can rearrange the formula to find the temperature change and subtract from the initial temperature. Since heat was released, the process is exothermic.

Step-by-step explanation:

Calculating Temperature Change for a Lead Nugget

To determine the final temperature of a lead nugget after releasing heat, we can use the formula Q = mcΔT where Q is the heat transferred, m is the mass, c is the specific heat capacity of lead, and ΔT is the change in temperature. First, we need to convert 1,917.50 mg of lead to grams, which is 1.9175 g. As we weren't given the specific heat capacity, we'll assume a typical value for lead, which is approximately 0.128 J/g°C.

Given that the nugget released 26.78 J of heat, and assuming the specific heat capacity of lead is 0.128 J/g°C, we can rearrange the formula to solve for the change in temperature (ΔT): ΔT = Q / (mc). Plugging in the values, we have ΔT = 26.78 J / (1.9175 g * 0.128 J/g°C), which allows us to calculate ΔT. From there, we can subtract ΔT from the initial temperature of 25.40°C to find the final temperature.

As for whether this is an endothermic or exothermic process, since heat was released (as indicated by the positive value of heat transfer), the process is exothermic, which aligns with the typical behavior of a metal cooling and losing heat.

User TechSavy
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