187k views
4 votes
A −3 × 10−6 c charge is brought from a very distant point by an external force and placed at the origin. calculate the magnitude of the electric force on this charge. answer in units of n. 018 (part 4 of 4) 10.0 points calculate the work that had to be done by an external force to bring q to the origin from the distant point. answer in units of j.

2 Answers

4 votes

Final answer:

The magnitude of the electric force on the given charge is 9.00 × 10^(-1) N.

Step-by-step explanation:

The magnitude of the electric force on a charge can be calculated using the formula:

F = qE

where F is the electric force, q is the charge, and E is the electric field strength. In this case, the charge is -3 × 10^(-6) C and the electric field strength is 3.00 × 10^5 N/C. Plugging the values into the formula, we get:

F = (-3 × 10^(-6) C)(3.00 × 10^5 N/C) = -9.00 × 10^(-1) N

Therefore, the magnitude of the electric force on this charge is 9.00 × 10^(-1) N.

User Ayoob Khan
by
6.6k points
0 votes

Final answer:

The magnitude of the electric force on the charge is -9.0 × 10^-1 N. The work done by an external force to bring the charge to the origin is essentially zero.

Step-by-step explanation:

The magnitude of the electric force on the charge can be calculated by multiplying the charge by the electric field strength. In this case, the charge is -3 × 10-6 C and the electric field strength is 3.00 × 105 N/C. Therefore, the magnitude of the electric force is (-3 × 10-6 C) × (3.00 × 105 N/C) = -9.0 × 10-1 N.

The work done by an external force to bring the charge to the origin can be calculated using the formula: work = force × distance. Since the charge is brought from a very distant point, the distance can be considered infinite or very large. As a result, the work done is essentially zero.

User Harsh Agarwal
by
7.4k points