Final answer:
The general solutions for 'cos θ = √2/2' are θ = π/4 + 2kπ for the smaller angle and θ = 7π/4 + 2kπ for the larger angle, with k as any integer.
Step-by-step explanation:
The original question appears to contain typos and may be incorrect as it is currently written. The expression 'cos θ2= 2 2' does not make mathematical sense. Assuming the intended question is to write the general solution for the equation 'cos θ = √2/2', we can proceed with a solution.
The equation 'cos θ = √2/2' has solutions at θ = π/4 and θ = 7π/4 for the interval from 0 to 2π because the cosine function is positive in the first and fourth quadrants. Since cosine is periodic with period 2π, this means that the general solution for θ based on the smaller angle (which is the angle in the first quadrant), and allowing for all rotations, is:
θ = π/4 + 2kπ
where k is any integer.
To write the general solution for θ based on the larger angle (which is the angle in the fourth quadrant), we express it as:
θ = 7π/4 + 2kπ
Again, k represents any integer.
By ensuring that k is an integer, θ will always be in the range from 0 to 4π, meeting the requirements of the task.