Question

A string is wrapped around a disk of mass 2.4 kg and radius 0.10 m. Starting from rest, you pull the string with a constant force of 8 N along a nearly frictionless surface. At the instant when the center of the disk has moved a distance of x = 0.13 m, and your hand has moved a distance of d = 0.31 m, what is the work done by the force?

Answer 1

The work done by the pulling force on the disk is calculated using the formula W = F × d, which results in 2.48 Joules.

Step-by-step explanation:

To calculate the work done by a force, you use the formula W = F × d, where W is work, F is the magnitude of the force, and d is the distance over which the force is applied in the direction of the force.

In this scenario, the string is pulled a distance of d = 0.31 m with a force of F = 8 N. Since the surface is nearly frictionless, we can assume that the pulling force is directly converted into work done on the disk.

Therefore, the work done by the pulling force is:

W = F × d
W = 8 N × 0.31 m
W = 2.48 J

The work done on the disk by the pulling force is 2.48 Joules.