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Solve the inequality. 2(4 + 2x) ≥ 5x + 5? A. x ≤ 3 B. x ≤ 2 C. x ≥ 3 D. x ≥ 2

User Thibault J
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2 Answers

4 votes

Answer: C

Step-by-step explanation:

Expand first:

2(4 + 2x) ≥ 5x + 5

8 + 4x ≥ 5x + 5

isolate for x

4x-5x ≥ 5 - 8

-x ≥ -3

x ≥ 3

Treat the inequality sign as an = sign

User RunOrVeith
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3 votes

Final answer:

The solution to the inequality 2(4 + 2x) ≥ 5x + 5 is x ≤ 3. Option A is correct.

Step-by-step explanation:

To solve the inequality 2(4 + 2x) ≥ 5x + 5, let's first distribute the 2 on the left side of the inequality:

8 + 4x ≥ 5x + 5

We then move all terms containing x to one side:

4x - 5x ≥ 5 - 8

Simplify the terms:

-x ≥ -3

Now, to get the inequality in terms of positive x, we will multiply both sides by -1, remembering to reverse the inequality sign, as multiplying or dividing by a negative number inverts the inequality:

x ≤ 3

The solution is that x must be less than or equal to 3, denoted as x ≤ 3.

User Mattorb
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