Question

The beginning of an arithmetic sequence is shown below 15,23,31,39 find 11th term

Answer 1

a₁₁ = 95

Explanation:

the nth term of an arithmetic sequence is

`a_(n)` = a₁ + (n - 1)d

a₁ is the first term , d the common difference , n the term number

here a₁ = 15 and d = a₂ - a₁ = 23 - 15 = 8 , then

a₁₁ = 15 + (10 × 8) = 15 + 80 = 95