Question

I beg help im in desperate need due in an hour

Answer 1

The simplified expression of 3a - ¹/₄ (c - b) is determined as
`\left (\begin{array}{c}-22&20\end{array}\right)`

How to calculate the value of the expression?

The given expression is simplified by applying the following formula as shown below;

The given expression include;

`a = \left (\begin{array}{c}-8&7\end{array}\right)`

`b = \left (\begin{array}{c}8&-20\end{array}\right)`

`c = \left (\begin{array}{c}0&-16\end{array}\right)`

The required expression to be calculated include;

= 3a - ¹/₄ (c - b)

We will simplify each expression as follows;

`3a = 3\left (\begin{array}{c}-8&7\end{array}\right)\\\\\\3a = \left (\begin{array}{c}-24&21\end{array}}\right)`

`c - b = \left (\begin{array}{c}0&-16\end{array}\right) - \left (\begin{array}{c}8&-20\end{array}\right)\\\\\\c - b = \left (\begin{array}{c}-8&4\end{array}\right)`

`(1)/(4) (c - b) = \left (\begin{array}{c}-8/4&4/4\end{array}\right)\\\\\\\\(1)/(4) (c - b) = \left (\begin{array}{c}-2&1\end{array}\right)`

The final expression becomes;

`3a - (1)/(4) (c - b) = \left (\begin{array}{c}-24&21\end{array}}\right) - \left (\begin{array}{c}-2&1\end{array}}\right)\\\\\\3a - (1)/(4) (c - b) = \left (\begin{array}{c}-22&20\end{array}}\right)`