Question

In one city of balloons of 1.2 l filled air at 101 gpa pressure the balloon is then the second city at a much higher altitude at the 2nd atm pressure is 89 gpa if the temperature is the same in both places what will be the new volume of the balloon

Answer 1

The new volume of the balloon is 1.366 L.

Step-by-step explanation:

Boyle's law states that for a given amount of gas at a constant temperature, the volume of the gas is inversely proportional to the pressure of the gas. This means that as the pressure of a gas increases, the volume of the gas decreases, and vice versa.

We can use Boyle's law to calculate the new volume of the balloon in the second city. We know that the initial volume of the balloon is 1.2 L and the initial pressure is 101325 Pa. We also know that the final pressure is 89000 Pa. Since the temperature is the same in both cities, we can assume that it is constant.

Therefore, we can plug these values into Boyle's law to solve for the final volume:

V1 * P1 = V2 * P2

where:

V1 is the initial volume (1.2 L)

P1 is the initial pressure (101325 Pa)

V2 is the final volume (unknown)

P2 is the final pressure (89000 Pa)

Solving for V2, we get:

V2 = (V1 * P1) / P2 = (1.2 L * 101325 Pa) / 89000 Pa = 1.366 L

Therefore, the new volume of the balloon in the second city is 1.366 L.