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Question 5941: Suppose \( f(x) = \ln(f(x)) \), where \( f(x) > 0 \) for all real numbers and is differentiable for all real numbers. If \( f(4) = 2 \) and \( f'(4) = -\frac{1}{5} \), find \( g'(4) \). a) g'(4) = 1/4 b) g'(4) = - - 1/2 c) g'(4) = 1/5 d) g'(4) = - -1/10

User SJMan
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Final Answer:

Presuming that \( g(x) \) was meant to be mentioned in the problem, let's assume the function \( g(x) \) is defined by:
\[ g(x) = \ln(f(x)) \] \( g'(4) = -\frac{1}{10} \), which corresponds to option D

Step-by-step explanation:

To solve this question, we need to clarify the probable mistake in the given equation \( f(x) = \ln(f(x)) \), since it doesn't make sense for \( f(x) \) to be equal to its natural logarithm in general.


We are given \( f(4) = 2 \) and \( f'(4) = -\frac{1}{5} \), and we want to find the derivative of \( g(x) \) at \( x = 4 \). We can find \( g'(x) \) by applying the chain rule for differentiation, which states that if \( g(x) = h(f(x)) \), then
\[ g'(x) = h'(f(x)) \cdot f'(x) \]

In our case, \( h(x) \) would be the natural logarithm function \( \ln(x) \), therefore
\[ h'(x) = \frac{1}{x} \]

Now, we apply the chain rule for the function \( g(x) = \ln(f(x)) \):
\[ g'(x) = h'(f(x)) \cdot f'(x) = \frac{1}{f(x)} \cdot f'(x) \]

We substitute \( x = 4 \):
\[ g'(4) = \frac{1}{f(4)} \cdot f'(4) \]

We were given:
\[ f(4) = 2 \quad \text{and} \quad f'(4) = -\frac{1}{5} \]

Substitute these values in the expression for \( g'(4) \):
\[ g'(4) = \frac{1}{2} \cdot \left(-\frac{1}{5}\right) = -\frac{1}{2} \cdot \frac{1}{5} = -\frac{1}{10} \]

Therefore, \( g'(4) = -\frac{1}{10} \), which corresponds to option D

User Nayda
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