Question

what happens when chlorine is passed into a solution og sulphur (iv) oxide in water? How would you identify all the products formed? Give the equation for the reaction and the identification tests​

Answer 1

When chlorine is passed into a solution of sulfur(IV) oxide in water, it forms chlorosulfonic acid (HSO3Cl) and hydrochloric acid (HCl).

Step-by-step explanation:

Chlorine reacts with sulfur(IV) oxide in water to produce chlorosulfonic acid and hydrochloric acid. The balanced chemical equation for the reaction is:

SO2 (g) + 2Cl2 (g) + 2H2O (l) -> HSO3Cl (aq) + 2HCl (aq)

To identify the products:

Chlorosulfonic Acid (HSO3Cl): It is a colorless liquid and can be identified by its characteristic acidic properties.

Hydrochloric Acid (HCl): It is a strong acid, identified by its ability to turn blue litmus paper red and evolve gas when reacted with a metal.

Confirmation tests, such as pH indicators and chemical tests for chloride ions, can be employed to identify the specific products formed.