Final answer:
The velocity of ball A as it strikes the ground is approximately 15.47 m/s, while the velocity of ball B is approximately 16.94 m/s.
This correct answer is none of the above.
Step-by-step explanation:
To determine the velocity of the balls as they strike the ground, we can use the equations of motion.
For ball A, which is dropped from rest at a height of 12.3m, we can use the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (0 m/s for a dropped ball), a is the acceleration due to gravity (-9.8 m/s^2), and s is the distance traveled.
Plugging in the values, we get v^2 = 0 + 2(-9.8)(12.3), which simplifies to v^2 = -239.16. Since we only consider positive velocities, the velocity of ball A as it strikes the ground is approximately 15.47 m/s.
For ball B, which is thrown with an initial velocity of 6.35 m/s from a height of 25.0m, we can use the equation v^2 = u^2 + 2as. Plugging in the values, we get v^2 = (6.35)^2 + 2(-9.8)(25.0), which simplifies to v^2 = 286.75.
Therefore, the velocity of ball B as it strikes the ground is approximately 16.94 m/s.
This correct answer is none of the above.