Final answer:
To solve the quadratic equation 4x²+12x+5=0 using the quadratic formula, we substitute the values from the equation into the formula and simplify to find the solutions. The solutions are approximately -2.5 and -0.5 to 1 decimal place.
Step-by-step explanation:
To solve the quadratic equation 4x²+12x+5=0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax²+bx+c=0, the solutions for x are given by:
x = (-b ± √(b²-4ac)) / (2a)
Plugging the values from the given equation into this formula, we have:
a = 4
b = 12
c = 5
Substituting these values into the formula, we get:
x = (-12 ± √(12²-4*4*5)) / (2*4)
Simplifying further:
- x = (-12 ± √(144-80)) / 8
- x = (-12 ± √(64)) / 8
- x = (-12 ± 8) / 8
- x = -20/8 or -4/8
- x = -2.5 or -0.5
Therefore, the solutions to the equation 4x²+12x+5=0 are approximately -2.5 and -0.5 to 1 decimal place.
Learn more about Quadratic equations here: