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What is the perimeter of the polygon formed by the points A(-2,1), B(4,-1), C(-2,3)? a) 18.7 units b) 18.5 units c) 16.9 units d) 17.2 units

User Jacob Hyde
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1 Answer

3 votes

Answer:

The perimeter of the polygon formed by the points A(-2,1), B(4,-1), and C(-2,3) is 2√10 + 2√13 + 2 units.

None of the option is true.

Explanation:

To find the perimeter of the polygon formed by the points A(-2,1), B(4,-1), and C(-2,3), we need to calculate the distances between these points and add them together.

First, let's find the distance between points A and B. We can use the distance formula:

dAB = √((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates of points A(-2,1) and B(4,-1):

dAB = √((4 - (-2))^2 + (-1 - 1)^2)

= √((6)^2 + (-2)^2)

= √(36 + 4)

= √40

= 2√10

Next, let's find the distance between points B and C:

dBC = √((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates of points B(4,-1) and C(-2,3):

dBC = √((-2 - 4)^2 + (3 - (-1))^2)

= √((-6)^2 + (4)^2)

= √(36 + 16)

= √52

= 2√13

Finally, let's find the distance between points C and A:

dCA = √((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates of points C(-2,3) and A(-2,1):

dCA = √((-2 - (-2))^2 + (1 - 3)^2)

= √((0)^2 + (-2)^2)

= √(0 + 4)

= √4

= 2

Now, we can add up the distances to find the perimeter:

Perimeter = dAB + dBC + dCA

= 2√10 + 2√13 + 2

Thus,

None of the option is true.

User Diego Melo
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7.3k points