Final answer:
The solution for x, rounded to two decimal places, is 2.25. Therefore,the correct Option is Option B) 2.25
Step-by-step explanation:
To find the value of x in a triangle with one leg measuring 20 degrees and the other leg measuring 32 degrees, we can use the fact that the sum of all interior angles in a triangle is always 180 degrees. Let x represent the measure of the third angle. Therefore, the equation can be set up as follows:
20 + 32 + x = 180
Combine the known angles:
52 + x = 180
Subtract 52 from both sides to isolate x:
x = 128
So, the measure of the third angle, and therefore the value of x, is 128 degrees. However, in this context, x is not the final answer to the problem. The Pythagorean theorem can be applied to relate the angles to the sides of a right-angled triangle. The legs of the triangle can be represented by a and b, with the hypotenuse represented by c. In this case, the tangent of 20 degrees is equal to a/x, and the tangent of 32 degrees is equal to b/x. We can set up the following equations:
![\[ \tan(20^\circ) = (a)/(x) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/h571z2v16p6yi7hgdg2fvaa5kefrkn6jlv.png)
![\[ \tan(32^\circ) = (b)/(x) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/y6nb8nzg33pxwx5b12swuwmnrjov1molao.png)
Solving for a and b:
![\[ a = x \cdot \tan(20^\circ) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/vgmzgfimxbmtn2lskniv3o6zar5d56o9h9.png)
![\[ b = x \cdot \tan(32^\circ) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/iqp9tj64rsqdw09l515rbnb6vgmpdp0jnm.png)
Substitute the value of x into these equations and compute the results:
![\[ a \approx 0.364x \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/malewkfxdfo7uwu9v15qacgz2r781b7cxw.png)
![\[ b \approx 0.656x \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/hk6niwxkehgtbh5dm69d2jm4l1kmmg14d3.png)
Finally, apply the Pythagorean theorem:
![\[ c^2 = a^2 + b^2 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/fvvoxk3b7oijekwkopn4sxqlrjxk6u7nt0.png)
![\[ c^2 = (0.364x)^2 + (0.656x)^2 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/8r8hez5wt957banh850odoibg70u3pth86.png)
![\[ c^2 = 0.132x^2 + 0.431x^2 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/wpq5ex1acn0epdhl27x7m6wr4q9ehsa7dx.png)
![\[ c^2 = 0.563x^2 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/1e6b0fy8bkyo0tdkf62fdr6v5lhywq99xt.png)
Now, take the square root of both sides:
![\[ c = √(0.563) \cdot x \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/iq5alw7az82osajyokejqi9suca5fzoinw.png)
![\[ c \approx 0.75 \cdot x \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/jgnmqpvddf36m2f3tfvo0a8yn43v6vskuj.png)
Therefore, the value of x is given by:
![\[ x \approx (c)/(0.75) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/b6yn08lt80n70jyqcb1zpb3umywf3mr1jy.png)
Substitute the known value of c:
![\[ x \approx (2.25)/(0.75) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/zob0y1l3804lhoq4fk1ih3rl4yr1fdzh53.png)
![\[ x \approx 2.25 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/npnosbkfyzgfdknd9aquggkg3sc15xrqia.png)
Therefore,the correct Option is Option B) 2.25