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When 14.9 g of Mg reacts, what volume of H2 gas, in liters, is produced at 24 °C and 835 mmHg? a) 0.317 L b) 1.27 L c) 2.54 L d) 5.08 L

1 Answer

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Final Answer:

When 14.9 g of Mg reacts, the volume of H2 gas produced at 24 °C and 835 mmHg is 2.54 L (Option C).

Step-by-step explanation:

To find the volume of H2 gas produced, we can use the ideal gas law: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature. First, determine the number of moles of Mg using its molar mass. Then, apply the ideal gas law to find the volume of H2 gas. Ensure that temperature is in Kelvin by adding 273.15 to the Celsius temperature. Given the pressure (835 mmHg), the calculated volume is 2.54 L.

Option C is the answer.

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