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: In the circuit, the total current is 60 A and the voltage is 240 V. If R1's resistance is 20 Ω, what is R2's resistance, in ohms?

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Final answer:

Using Ohm's Law, we calculate the total resistance of the circuit to be 4 Ω with a total current of 60 A and total voltage of 240 V. Since R1 is given as 20 Ω, there's an implied inconsistency because the total resistance of a series circuit cannot be less than any single resistance within it.

Step-by-step explanation:

To determine R2's resistance, we begin with the total voltage of the circuit which is 240 V, and the total current which is 60 A. We can calculate the total resistance of the circuit using Ohm's Law which states Voltage (V) = Current (I) x Resistance (R). Therefore, the total resistance (Rtot) of the circuit is Rtot = V / I = 240 V / 60 A = 4 Ω.

Given that R1 has a resistance of 20 Ω, and assuming that R1 and R2 are the only resistors in series in the circuit, which is not explicit in the question but implied as necessary information to solve the problem, R2's resistance can now be found. In a series circuit, resistances are additive, so Rtot = R1 + R2. With Rtot being 4 Ω and R1 being 20 Ω, this would imply an inconsistency as R1 cannot be greater than the total resistance of a series circuit, indicating that there may be a misunderstanding in the question as presented.

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