Final Answer:
The domain of
is
or
![\( (-\infty, 2.5] \).](https://img.qammunity.org/2024/formulas/mathematics/high-school/lv0jdvtgq8m6ncgdkzw5kj8h7l0hnh06di.png)
Step-by-step explanation:
The logarithm function
is defined only for positive arguments. In this case, the argument inside the logarithm,
, must be greater than zero. So, we set the inequality
and solve for ( x):
![\[ 5 - 2x > 0 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/9f8c6eyyi5h130xcsl245ufo4hn2ncyw9w.png)
Subtract 5 from both sides:
![\[ -2x > -5 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/i64gtrkmmh9lkfnj2ccsk54o6wlemh8z5d.png)
Divide both sides by -2 (note that dividing by a negative number reverses the inequality sign):
![\[ x < (5)/(2) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/8lpp46d88smjf25shtu8o1xcrsgqv4cdt1.png)
So, the domain is
or, in interval notation,
.
It's important to note that the domain is inclusive of
because at
, the argument
becomes zero, making the logarithm defined. Beyond ( x = 2.5), the argument becomes negative, leading to an undefined logarithm, and thus,
