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A glass jar contains 3 red, 13 green, 4 blue, and 8 yellow marbles. If a single marble is chosen at random from the jar, what is the probability of choosing a(a) red marble? (b) green marble? (c) blue marble?

User Andy Kaufman
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1 Answer

23 votes
23 votes

Solution

(a) red marble?


p=\frac{\text{red}}{\text{total}}=(3)/(3+13+4+8)=(3)/(28)

(b) green marble?


p=\frac{\text{gren}}{\text{total}}=(13)/(3+13+4+8)=(13)/(28)

(c) blue marble?​


p=\frac{\text{blue}}{\text{total}}=(4)/(3+13+4+8)=(4)/(28)

User Nikos Kazazakis
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