Question

In a physics lab, two carts labeled an and B are at rest on a low friction track. A spring like plunger connects them. The springs are compressed and then suddenly released, exerting explosion forces on each of the two carts. Car is 1/3 as mass of his car B during the explosion what is the force the acceleration the impulse and the momentum change

Answer 1

Cart A has 1/3rd the mass of Cart B. The force experienced by Cart A will be 1/3rd the force experienced by Cart B during the explosion. The impulse and momentum change can be calculated using formulas. Let's find :-

Now,

According to the question, cart A has 1/3rd of the mass of cart B. Let's assume the mass of cart A is mA and the mass of cart B is mB.

Therefore, we can write the equation mA = (1/3)mB.

The force experienced by each cart during the explosion can be calculated using Newton's Second Law, F = ma, where F is the force, m is the mass, and a is the acceleration.

Since cart A has 1/3rd of the mass of cart B, the force experienced by cart A will also be 1/3rd of the force experienced by cart B.

The impulse experienced by each cart during the explosion can be calculated using the equation, impulse = force * time. The momentum change can be calculated using the equation, momentum change = mass * velocity.