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Please help me solve this.​

Please help me solve this.​-example-1
User DWX
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1 Answer

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The distance from port Q to the lighthouse L is 18.44 km

The bearing of port Q from the lighthouse L is 282.53°. ​

How do we find the distance and bearing?

Distance = Speed × Time

1.5hr × 12 m = 18km

The distance Aleena sails from port P to port Q is indeed 18 km when sailing for 1 and a half hours at an average speed of 12 km/h.

Aleena sails 18 km from port P to port Q.

port Q to the lighthouse L, → the scale given: 1 cm represents 4 km.

length on the diagram from P to Q

Length on diagram (in cm) = (actual length in km)/(Scale conversion factor (in km/cm))

18km/4 = 4.5

For the Pythagorean theorem:

c² = a² + b²

(QL) = √(Length LP)² +(Length PQ)²

(QL) = √(1² + 4.5² )

(QL) = √(1 + 20.25)

(QL) = 4.609

Actual distance (QL)=4.61 cm × 4 km/cm

Actual distance (QL) ≈ 18.44 km

tangent of the angle (θ) at lighthouse L:

tan(θ) = opposite/Adjacent = length PQ/Length LP

θ = arctan ( length PQ/Length LP)
Bearing of Q from L= 360° − θ

Given that we calculated Length PQ to be 4.5 cm and Length LP to be 1 cm, let's use these values to find the bearing.

The angle θ at lighthouse L, calculated using the correct lengths, is approximately 77.47°. This angle is measured from the east direction towards port Q.

To find the bearing of port Q from the lighthouse L, which is measured clockwise from north, we subtract this angle from 360°:

Bearing of Q from L=360°−θ

Bearing of Q from L=360°−77.47°

Bearing of Q from L = 282.53°


User Chintan Bawa
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