Final Answer:
The percent yield of the experiment is c. 63.4%.the theoretical yield and applying the formula for percent yield [(actual yield / theoretical yield) * 100], the result comes out to be 63.4%.
Step-by-step explanation:
Percent yield is calculated by dividing the actual yield by the theoretical yield and then multiplying by 100. In this case, the actual yield is 4.27 g of Cu(C7H4SO3N)2(H2O)4·2 H2O.
The theoretical yield can be calculated from the amount of Cu(C2H3O2)2·H2O used initially. By comparing the actual and theoretical yields, the percent yield is found to be 63.4%, indicating the efficiency of the chemical reaction in producing the desired compound.
In chemistry, percent yield measures the efficiency of a reaction in producing the desired product. It is calculated by comparing the actual yield obtained from the experiment to the theoretical yield predicted by stoichiometry.
The given problem provides the actual yield of the compound Cu(C7H4SO3N)2(H2O)4·2 H2O as 4.27 g. To calculate the theoretical yield, one needs to use the initial amount of Cu(C2H3O2)2·H2O used in the reaction. By comparing the actual yield to the theoretical yield and applying the formula for percent yield [(actual yield / theoretical yield) * 100], the result comes out to be 63.4%. This percentage indicates the efficiency of the reaction in producing the desired compound, Cu(C7H4SO3N)2(H2O)4·2 H2O, from the given reactants. The calculated percent yield helps assess the success and efficiency of the chemical process in converting reactants into the intended product.