1) The average titer is 22.55 mL
2) The number of moles is 0.000187 moles
3) The reacted moles is 0.0000935 moles
4) The mass of fumaric acid is 0.011 g
5) The percentage of Fumaric acid is 0.55%
6) The percentage of carbon is 41.4%
What is titration?
1) To obtain the average titer;
22.24 + 22.36 + 23.32 + 22.28/4
= 22.55 mL
2) Number of moles of NaOH = 0.0083 M * 22.55/1000
= 0.000187 moles
3) If 1 mole of fumaric acid reacts with 2 moles of NaOH
x moles of fumaric acid reacts with 0.000187 moles of NaOH
x = 0.0000935 moles
4) Mass of the Fumaric acid = 0.0000935 moles * 116 g/mol
= 0.011 g
5) Mass percent of Fumaric acid in the tablet = 0.011 g/2 g * 100/1
= 0.55%
6) Percentage by mass of carbon in Fumaric acid; 4 * 12/116 * 100/1
= 41.4%