Question

two airplanes leave an airport at the same time. their speeds are 130 mph and 150 mph. one of the airplanes flies in the direction n 63rd^\circle, and the other in the direction s 81^\circle. how far apart are they after 1.5 hours?

Answer 1

To find the distance between the two airplanes after 1.5 hours, we can calculate the distance each airplane has traveled using distance = speed × time. We can then use the Pythagorean theorem to find the distance between the airplanes.

Step-by-step explanation:

To find the distance between the two airplanes after 1.5 hours, we need to calculate the distance each airplane has traveled. We can use the formula: distance = speed × time. For the first airplane, its speed is 130 mph, so the distance it has traveled is 130 mph × 1.5 hours = 195 miles. For the second airplane, its speed is 150 mph, so the distance it has traveled is 150 mph × 1.5 hours = 225 miles.

To find the distance between the two airplanes, we can use the Pythagorean theorem. The two distances form the sides of a right triangle, and the distance between the airplanes is the hypotenuse. Using the formula: distance = √(a² + b²), where a and b are the two distances, we can calculate the distance. Plugging in the values, we get: distance = √(195² + 225²) ≈ 293.64 miles.