Final answer:
To find the minimum mass of hydrobromic acid left over after the reaction with sodium hydroxide, we need to find the limiting reactant. After calculating the moles of each reactant, hydrobromic acid is the limiting reactant with 0.346 moles. Thus, there would be no hydrobromic acid left over, and the minimum mass of hydrobromic acid remaining is 0 grams.
Step-by-step explanation:
To calculate the minimum mass of hydrobromic acid that could be left over by the chemical reaction between hydrobromic acid and sodium hydroxide, we first need to determine the limiting reactant. The balanced chemical equation for the reaction is:
HBr (aq) + NaOH (aq) → NaBr (aq) + H₂O (l)
From the stoichiometry of the equation, we know there is a 1:1 molar ratio between hydrobromic acid and sodium hydroxide. We need to calculate the number of moles of each reactant:
- The molar mass of HBr is approximately 81 g/mol.
- The molar mass of NaOH is approximately 40 g/mol.
Moles of HBr = 28 g HBr × (1 mol HBr / 81 g HBr)
= 0.346 moles HBr
Moles of NaOH = 22.7 g NaOH × (1 mol NaOH / 40 g NaOH)
= 0.568 moles NaOH
In this case, it is clear that hydrobromic acid is the limiting reactant since there are fewer moles of HBr than NaOH. Therefore, no HBr will be left over, and the minimum mass of hydrobromic acid left over by the reaction is 0 grams.