Question

a train is traveling northeast at a rate of 25 ft/s along a track that is elevated 20 ft above the ground. the track passes over the street below at an angle of 300 . five seconds after the train passes over the road, a car traveling east passes under the tracks going 40 ft/s. how fast are the train and the car separating 3 seconds after the car passes under the tracks?

Answer 1

The train and the car separate by a distance of 80 ft after 3 seconds.

Step-by-step explanation:

To find the speed of the train and the car separating 3 seconds after the car passes under the tracks, we need to determine their respective distances from the starting point at that time.

Since the train has been traveling for 8 seconds (3 seconds after the car passes under the tracks + 5 seconds after the train passes over the road), it has traveled a distance of 25 ft/s x 8 s = 200 ft.

Similarly, the car has been traveling for 3 seconds and at a speed of 40 ft/s, so it has traveled a distance of 40 ft/s x 3 s = 120 ft.

Therefore, the train and the car are separating by a distance of 200 ft - 120 ft = 80 ft after 3 seconds.