We fail to reject te Null and conclude that mean weight is > 16 ounces.
Using the parameters given for our Calculation;
- μ = 16.05
- σ = 0.03
- sample size , n = 50
The Null and Alternative hypothesis;


We calculate the test statistic;
Test statistic =
- (16.05 - 16) / (.03/√50) = 11.785
Using the P - value calculator :
Pvalue(11.785) at 0.05 level of significance is < 0.00001
Since, the Pvalue < 0.05, Then the result is significant at 0.05.
Hence, we do not reject the Null and conclude that the mean weight is greater than 16 ounces .