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there are 3 tribes in a jungle that decided to hold a meeting. tribe a sent out 3 men. tribe b and c sent out 5 men together since they are in alliance. the nominated 8 men need to stand in line. how many ways are there so that no men from tribe a to be next to each other? show all your work.

User Abhay
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1 Answer

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There are 39500 ways for the 8 men to stand in line such that no men from Tribe A are next to each other.

How to find amount?

Consider the restriction that no men from Tribe A should be next to each other. Use the principle of permutations.

First, consider the total number of ways the 8 men can stand in line without any restrictions, then the ways Tribe A men can be together. Since there are 3 men from Tribe A, they can be arranged among themselves in 3! ways.

The men from Tribe B and C can also be arranged among themselves in 5! ways.

Now, the total number of arrangements where men from Tribe A are together is:

3! × 5!.

To find the total number of arrangements where no men from Tribe A are next to each other, subtract the above result from the total number of arrangements without any restrictions:

Total arrangements without restriction - Arrangements with Tribe A together = 8! - (3! × 5!)

8! - (3! × 5!) = 40320 - (6 × 120)

= 40320 - 720

= 39500

Therefore, there are 39500 ways for the 8 men to stand in line such that no men from Tribe A are next to each other.

User Zachary Yates
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