Question

shortly after a vinyl record (radius 0.152 m ) starts rotating on a turntable, its angular velocity is 1.60 rad/s and increasing at a rate of 8.00 rad/s2 . at this instant, for a point at the rim of the record, what is the tangential component of acceleration? express your answer with the appropriate units.

Answer 1

The tangential component of acceleration for a point at the rim of a vinyl record, with an angular acceleration of 8.00 rad/s^2 and a radius of 0.152 m, is calculated to be 1.216 m/s^2.

Step-by-step explanation:

The question asks for the tangential component of acceleration for a point at the rim of a vinyl record.

Given that the angular acceleration is 8.00 rad/s2 and the radius of the record is 0.152 m, we can calculate the tangential acceleration using the formula at = α * r, where at is the tangential acceleration, α is the angular acceleration, and r is the radius of the rotation.

By substituting the given values into the formula, we get:

a_t = 8.00 rad/s2 * 0.152 m,

which results in a tangential acceleration of 1.216 m/s2 at the rim of the record.