Question

a hydraulic lift is used to lift a car. the small piston has an area of 5 cm^2 and the large piston has an area of 50 cm^2. if a driver applies a force of 65 n to the small piston, what is the weight of the car the large piston can support

Answer 1

The force exerted on the large piston in a hydraulic lift can be calculated using Pascal's principle and the ratio of the areas of the large and small pistons.Therefore, the large piston can support a weight of 650 N, which is the weight of the car resting on it.

Step-by-step explanation:

According to Pascal's principle, the force exerted on the large piston in a hydraulic lift is determined by the ratio of the areas of the large and small pistons. In this case, the area of the small piston (A1) is 5 cm^2 and the area of the large piston (A2) is 50 cm^2.

Using the formula F2 = (A2/A1) * F1, where F2 is the force on the large piston and F1 is the force on the small piston, we can calculate the force on the large piston:

F2 = (50 cm^2 / 5 cm^2) * 65 N

= 650 N.

Therefore, the large piston can support a weight of 650 N, which is the weight of the car resting on it.