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a block of unknown mass is attached to a spring of spring constant 9.3 n/m and undergoes simple harmonic motion with an amplitude of 13.1 cm. when the mass is halfway between its equilibrium position and the endpoint, its speed is measured to be 25.4 cm/s. calculate the mass of the block. answer in units of kg.

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To find the mass of the block, use the equation for the period of simple harmonic motion and plug in the given values for the amplitude and speed of the block. Therefore, the mass of the block will be 0.218 kg.

To find the mass of the block, we can use the equation for the period of simple harmonic motion: T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant.

The period can be calculated using the speed and amplitude of the block: T = 2πA/v, where A is the amplitude and v is the speed. Plugging in the given values, we can solve for the mass:

T = 2π(13.1 cm)/(25.4 cm/s) = 0.518 s
0.518 s = 2π√(m/9.3 N/m)
0.2697 = √(m/9.3 N/m)
m/9.3 N/m = (0.2697)²
m = (0.2697)² x 9.3 N/m
m ≈ 0.218 kg

Therefore, the mass of the block will be 0.218 kg.