Question

The discharge of a pump is 3 m above the inlet. Water enters at a pressure of 138 kPa and leaves at a pressure of 1380 kPa. The specific volume of the water is 0.001 m3/kg. If there is no heat transfer and no change in kinetic or internal energy, what is the work per unit mass

Answer 1

The answer is "
`1.271 \ (KJ)/(kg)\\`"

Step-by-step explanation:

`\Delta e_(mech) =(P_2-P_1)/(P) + (v_(2)^2-v_(1)^2)/(2)+g(z_2-z_1)\\\\\Delta e_(mech) =( 1380 -138 * 1000 )/(1000) + 0+g(3-0)\\\\P = (1)/(v)= (1)/(0.001) = 1000 (kg)/(m) \\\\ \Delta e_(mech) =1242 +9.81(3)= 1271.43 (J)/(kg) \\\\\text{work per unit pass}= 1.271 \ (KJ)/(kg)\\`