Therefore, the animal scientist needs a sample size of at least 274 heifers.
To solve this problem
we can use the following formula:
n = \frac{p(1-p)}{Z^2/4(e)^2}
where:
The sample size is denoted by n.
The percentage of heifers who need assistance is denoted by p (0.20).
The desired confidence level's z-score, Z, is 1.96 for a 90% confidence level.
The margin of error, or e, is 0.05.
Entering the values yields:
N equals \frac{0.2(1-0.2)}.{1.96^2/4(0.05)^2}
n equals 273.18.
In order to estimate the percentage of heifers who require assistance with a margin of error of 0.05 and a confidence level of 0.90, the animal scientist needs a sample size of at least 274 heifers.