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a long, straight solenoid with a cross-sectional area of8.00 cm2is wound with 90 turns of wire per centimeter, and thewindings carry a current of 0.350 a. a second winding of 12 turnsencircles the solenoid at its center. the current in the solenoid isturned off such that the magnetic field of the solenoid becomeszero in 0.0400 s. what is the average induced emf in the secondwinding?

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The average induced emf in the second winding can be calculated using Faraday's law of electromagnetic induction. The formula for calculating the induced emf is (Magnetic field x Cross-sectional area x Number of turns in the second winding x Rate of change of magnetic field) / Time. Plugging in the given values, the average induced emf is -268.8 V.

The average induced emf in the second winding can be calculated using Faraday's law of electromagnetic induction. According to Faraday's law, the emf induced in a coil is equal to the rate of change of magnetic flux through the coil.

The magnetic flux through the coil can be found by multiplying the magnetic field produced by the solenoid by the cross-sectional area of the coil. The rate of change of magnetic field can be obtained by dividing the initial magnetic field by the time it takes to decrease to zero. Therefore, the average induced emf can be calculated as follows:

emf = (Magnetic field x Cross-sectional area x Number of turns in the second winding x Rate of change of magnetic field) / Time

Plugging in the given values:

emf = (0.350 A x 8.00 cm2 x 12 turns x (0 - 0 A / 0.0400 s)) / 0.0400 s

emf = - 268.8 V

Therefore, the average induced emf is -268.8 V.

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