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an it department has 15 members. they need to send some of their people into 3 teams, which are named a, b, c. if 5 employees are qualified for team a, 3 for team b, and the remaining 7 for team c. if each of the teams will only consist of 3 people, how many ways are there to choose these 3 teams? (you may assume no one person is qualified for more than one team.)

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Final answer:

There are 455 ways to choose the 3 teams.

Step-by-step explanation:

To determine the number of ways to choose the 3 teams, we can use combinations. Since each team consists of 3 people and we have 15 members in total, we need to find the number of ways to choose 3 people from 15. This can be calculated using the formula for combinations: C(15, 3).

C(15, 3) = 15! / (3!(15-3)!) = (15 * 14 * 13) / (3 * 2 * 1) = 455.

Therefore, there are 455 ways to choose the 3 teams.

User Jemminger
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