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kara less was applying her makeup when she drove into south's busy parking lot last friday morning. unaware that lisa ford was stopped in her lane 30 feet ahead, kara rear-ended lisa's rented taurus. kara's 1300-kg car was moving at 11 m/s and stopped in 0.14 seconds. (a) determine the momentum change of kara's car. (b) determine the impulse experienced by kara's car. (c) determine the magnitude of the force experienced by kara's car.

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Final answer:

To answer the student's question: (a) The momentum change of Kara's car is 14300 kg*m/s. (b) The impulse experienced by the car is also 14300 kg*m/s. (c) The magnitude of the force experienced by the car is 102142.86 N.

Step-by-step explanation:

The question you've asked pertains to the principles of momentum and impulse in a car collision. Here's how you can determine momentum change, impulse, and force experienced by Kara's car in the collision:

(a) Momentum change (Δp) of Kara's car can be calculated using the formula Δp = m * Δv, where m is the mass of the car and Δv is the change in velocity. Since the car comes to a stop, Δv is just the initial velocity (11 m/s).

(b) Impulse (J) experienced by the car is equal to the change in momentum, so J = Δp.

(c) Magnitude of the force (F) experienced by Kara's car is found using the impulse-momentum theorem, J = F * Δt, where Δt is the time over which the force acts.

For the calculation: Kara's car with a mass of 1300 kg, initial velocity of 11 m/s, and a stopping time of 0.14 s.

(a) Δp = m * Δv = 1300 kg * 11 m/s = 14300 kg*m/s

(b) J = Δp = 14300 kg*m/s

(c) F = J / Δt = 14300 kg*m/s / 0.14 s = 102142.86 N (assuming acceleration is constant)

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