Question

. when a person sings, his or her vocal cords vibrate in a repetitive pattern having the same frequency of the note that is sung. if someone sings the note b flat that has a frequency of 466 hz , how much time does it take the person's vocal cords to vibrate through one complete cycle, and what is the angular frequency of the cords? please enter your answers in the order time, angular frequency separated with comma.

Answer 1

To sing a B flat note at 466 Hz, it takes approximately 0.002145 seconds for a person's vocal cords to go through one complete cycle, and the angular frequency is about 2927.04 radians per second.

Step-by-step explanation:

When a person sings the note B flat with a frequency of 466 Hz, the vocal cords complete one vibration cycle in a certain amount of time.

This time period can be found by taking the reciprocal of the frequency.

So, the time (T) it takes for one complete cycle is T = 1/frequency = 1/466 Hz, which equals approximately 0.002145 seconds.

The angular frequency (ω) of the vocal cords is related to the frequency (f) by the equation ω = 2πf.

Therefore, the angular frequency for the B flat note is ω = 2π(466 Hz), which equals approximately 2927.04 radians per second.