Final answer:
In 1990, approximately 7 out of 20 new employees were estimated to be women, and in 1994, approximately 7 out of 20 new employees were also estimated to be women. The 95% confidence interval suggests that there is no evidence to conclude that the proportion of women hired as editorial staff was higher in 1994 compared to 1990.
Step-by-step explanation:
To estimate the number of women among the new employees in 1990, we can calculate 33.7% of 20, which is approximately 6.74. Since we can't have a fraction of a person, we can round this number to 7. Therefore, we can estimate that about 7 of the new employees in 1990 were women.
To estimate the number of women among the new employees in 1994, we can calculate 36.2% of 20, which is approximately 7.24. Rounding this number, we estimate that about 7 of the new employees in 1994 were women.
To compute the 95% confidence interval, we need to calculate the standard error for each proportion using the formula: SE = sqrt(p * (1-p) / n), where p is the proportion and n is the sample size. For 1990, the standard error is approximately 0.05 and for 1994, the standard error is approximately 0.056.
We can then calculate the difference between the two proportions, which is 0.362 - 0.337 = 0.025.
Using the formula: CI = difference +/- (Z * SE), where CI is the confidence interval, Z is the Z-score corresponding to the desired confidence level (1.96 for 95% confidence interval), and SE is the standard error, we can calculate the 95% confidence interval. For the difference of 0.025, the 95% confidence interval is approximately -0.042 to 0.092.