Question

a 1.70-kg disk with a rotational inertia given by mr2/2 is free to rotate on a fixed horizontal axis suspended from the ceiling. a string is wrapped around the disk and a 0.900-kg mass hangs from the free end. if the string does not slip as the mass falls and the cylinder rotates, what is the tension in the string?

Answer 1

The tension in the string is 8.82 N.

The tension in the string can be determined by considering the forces acting on the system. The weight of the hanging mass creates a tension force in the string, while the rotational motion of the disk introduces a centripetal force.

Since the string does not slip, the tension force is equal to the weight of the hanging mass. Using the given values, we can calculate the tension:

Tension = Weight of hanging mass = (mass of hanging mass) x (acceleration due to gravity) = (0.900 kg) x (9.8 m/s²) = 8.82 N

Therefore, the tension in the string is 8.82 N.