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suppose that the radius of the circular path is r when the speed of the rocket is v and the acceleration of the rocket has magnitude a. if the radius and speed are increased to 2r and 2v respectively, what is the magnitude of the rocket's subsequent acceleration?

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Final answer:

When both the radius and speed of a rocket on a circular path are doubled, the subsequent centripetal acceleration is twice the original acceleration, or 2a.

Step-by-step explanation:

The magnitude of Rocket's Subsequent Acceleration

The question concerns the centripetal acceleration experienced by a rocket moving in a circular path.

Initially, the rocket moves at speed v on a path with radius r and has a centripetal acceleration of magnitude a.

According to the formula for centripetal acceleration, ac = v2/r, if the radius (r) and speed (v) of the rocket are both doubled, the new centripetal acceleration can be calculated by plugging the new values into the formula, ac = (2v)2/(2r).

This simplifies to ac = 4v2/2r, which further simplifies to ac = 2v2/r.

Therefore, the new acceleration is twice the initial acceleration, so the rocket's subsequent acceleration would be 2a.

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