Question

(b) two water pipes are in series, so that the water flows through one pipe and then through the other. the first pipe has a fluid resistance of 4.53 kpa/m3 and the second has a resistance of 4.89 kpa/m3 what is the combined resistance of the two pipes?

Answer 1

The combined fluid resistance of two water pipes in series is the sum of their individual resistances, which is 9.42 kPa/m³.

Step-by-step explanation:

The combined fluid resistance of two water pipes connected in series can be found by simply adding their individual resistances together.

Given that the first pipe has a fluid resistance of 4.53 kPa/m³ and the second pipe has a resistance of 4.89 kPa/m³, the total resistance when these pipes are connected in series is:

Total Resistance = Resistance of Pipe 1 + Resistance of Pipe 2 = 4.53 kPa/m³ + 4.89 kPa/m³ = 9.42 kPa/m³.