Final Answer:
The vertical asymptotes of the graph of the function
are ( x = -5 ) and ( x = 1 ).
Step-by-step explanation:
To find the vertical asymptotes, we need to examine the denominator of the rational function since vertical asymptotes occur where the denominator equals zero. In this case, the denominator is
. Setting this equal to zero and solving for ( x ), we can factor the denominator:
![\[ x^3 + 5x^2 - x - n = 0 \]](https://img.qammunity.org/2024/formulas/mathematics/college/qjulqj0d3tfd2db32rs1ny4cpvfc806c8i.png)
![\[ (x + 5)(x - 1)(x + n) = 0 \]](https://img.qammunity.org/2024/formulas/mathematics/college/e49dg1znyp9ios9n1h6yjk2uzzmra5yrft.png)
Setting each factor equal to zero gives the possible values for
. However, we are asked to express the answer without ( n ) if possible. Since ( n ) is an arbitrary integer, it can take any value, and ( x = -n ) will vary accordingly. Therefore, we exclude ( x = -n ) from the final answer to provide a concise solution.
Therefore, the vertical asymptotes of the function are ( x = -5 \k) and ( x = 1 ). These are the values of ( x ) where the denominator becomes zero, resulting in an undefined fraction and the presence of vertical asymptotes in the graph of the function.