Question

\[ \begin{array}{llll} P(s 1)=0.75 & P(F)=0.8 & P(s 1 \mid F)=0.85 & P(s 1] U)=0.55 \\ P(s 2)=0.25 & P(U)=0.2 & P(s 2 \mid F)=0.15 & P(s 2 \mid U)=0.45 \end{array} \] Answer

Answer 1

The probability of event F (P(F)) is 0.8, indicating an 80% chance of occurrence based on the provided information.

Step-by-step explanation:

Probability theory involves assessing the likelihood of events occurring. In the given information, P(F) directly provides the probability of event F, and it is specified as 0.8. This numerical value indicates an 80% chance of event F happening within the set of possible outcomes.

To further understand the context, it's essential to grasp the concept of conditional probability. For instance, the probability of event \(S_1\) given that event F has occurred, denoted as \(P(S_1 \mid F)\), is 0.85. This means that if event F has taken place, there is an 85% chance of \(S_1\) occurring.

In probability calculations, these values help quantify the relationships between different events. The provided probabilities offer insights into the likelihood of specific outcomes, aiding in making informed decisions or predictions based on the given data.