Question

I need help with this table pleasecalculate relative density of steel. Use table 3

Answer 1

Take into account that the relative density is given by:

`\rho_{\text{rel}}=\frac{\rho}{\rho_{\text{water}}}`

where ρ, in this case, is the density of the steel and ρwater is the density of water (1000 kg/m^3).

The density of the steel is:

`\rho=\frac{\text{mass}}{\text{volume}}`

Based on table 3, you have:

mass = 50.7 g = 0.0507 kg

volume = 0.0000063 m^3

`\rho=(0.0507kg)/(0.0000063m^3)\approx8047.62(kg)/(m^3)`

Then, for the relative density you obtain:

`\rho_{\text{rel}}=\frac{\rho}{\rho_{\text{water}}}=(8047.62(kg)/(m^3))/(1000(kg)/(m^3))\approx8.048`

Hence, the relative density of steel is 8.048