Final Answer:
For any irrational number α, the corollary to Dirichlet's theorem asserts that there exist infinitely many distinct rational numbers
such that
. This result follows from the density of the fractional parts of positive integer multiples of α in the unit interval, allowing for the construction of an infinite sequence of rational approximations satisfying the given condition.
Step-by-step explanation:
Dirichlet's theorem states that for any two real numbers
and β with
, there exist infinitely many positive integers m and n such that
.
The corollary you provided is a special case of Dirichlet's theorem where
and
is an irrational number. The corollary states that for any irrational
, there exist infinitely many distinct rational numbers
such that
.
Let's prove this corollary:
Assume
is an irrational number. We want to show that there exist infinitely many distinct rational numbers
satisfying
.
Consider the sequence of fractional parts of the positive integer multiples of
:
![\[ \{ n\alpha \} = n\alpha - \lfloor n\alpha \rfloor \]](https://img.qammunity.org/2024/formulas/mathematics/college/5lnvyepi5u53zytjfvi0w0zorcbniv5a9u.png)
Since
is irrational, the sequence
is dense in the unit interval
. This means that for any small interval (a, b) where
, there exists a positive integer n such that
belongs to (a, b).
Now, let's choose a = 0 and
, where q is a positive integer. Since
can be found in the interval
for infinitely many n, there exist infinitely many positive integers n such that
.
This implies that there exist infinitely many positive integers n and
such that
. Rearranging, we have:
![\[ 0 < \alpha - (m)/(n) < (1)/(qn) \]](https://img.qammunity.org/2024/formulas/mathematics/college/aiuxhqdcwishuyad9gln5d9jw9rmy7hn4a.png)
Now, let p = m and q = n. We have shown that for infinitely many positive integers n, there exist corresponding positive integers m such that
.
Since
can be made arbitrarily small by choosing large enough n, we conclude that there exist infinitely many distinct rational numbers
such that
, proving the corollary.