Question

How much energy is required to freeze 20 ml of water already at 0.0 0C?

Answer 1

Given

Amount of water,

`m=20\text{ ml}`

Temperature is,

`T=0.00C`

To find:

Energy required to freeze the water.

Step-by-step explanation:

The latent heat of fusion is

`L=33.5*10^4\text{ J/}kg`

Converting the amount of water to kg,

`m=0.020kg`

Thus the energy required is:

`\begin{gathered} H=mL \\ \Rightarrow H=0.020*33.5*10^4=0.67*10^4J \end{gathered}`

Conclusion:

The amount of energy required is

`0.67*10^4J`