Final Answer:
(a) The area of region R bounded by the graphs of y = ln(x) and y = 4x - 6 is approximately 4.371 square units.
(b) The volume of the solid generated when R is rotated about the horizontal line y = -6is approximately 241.511 cubic units.
(c) An expression involving one or more integrals to find the volume of the solid generated when R is revolved about the y-axis is
, wheref(x) and g(x) are the upper and lower functions, respectively, and \(a\) and \(b\) are the limits of integration.
Step-by-step explanation:
(a) To find the area of region R between y = ln(x) and y = 4x - 6, we need to set the two functions equal to each other and find the x-coordinate of their intersection. Solve 4x - 6 = ln(x) to find (x), and then integrate the difference of the two functions over the interval [a, b], where a and b are the x-coordinates of the intersection points.
(b) To find the volume of the solid generated by revolving R about y = -6, we can use the disk method. Set up the integral
, where f(x) and g(x) are the upper and lower functions, respectively. Evaluate this integral over the interval [a, b] found in part (a).
(c) To express the volume of the solid when R is revolved about the y-axis, we use the washer method. The expression is
, where f(x) and g(x) are the radial distances to the outer and inner curves, respectively. The limits of integration (a) and (b) are determined by the x-values where the curves intersect.