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Will crown best answer

Will crown best answer-example-1
User Rojeeer
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1 Answer

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The standard deviation of the distribution is 1.92

How to determine the standard deviation of the distribution

From the question, we have the following parameters that can be used in our computation:

The table of values

Where, we have

x P(x)

0 0.1

1 0.2

2 0.1

3 0.6

Start by calculating the expected value using

E(x) = Sum of x * P(x)

So, we have

E(x) = 0 * 0.1 + 1 * 0.2 + 2 * 0.1 + 3 * 0.6

E(x) = 2.2

Next, we have

E(x²) = 0 * 0.1² + 1 * 0.2² + 2 * 0.1² + 3 * 0.6²

E(x²) = 1.14

So, we have

Var(x) = [E(x)]² - E(x²)

This gives

Var(x) = (2.2)² - (1.14)

Var(x) = 3.7

Lastly, we have

SD(x) = √3.7

SD(x) = 1.92

Hence, the standard deviation of the distribution is 1.92

User Shifra
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