Final Answer:
1. \(P(\text{Small and Breaks Down}) = 0.13 \times 0.87 = 0.1131\)
2. \(P(\text{Small and Does Not Break Down}) = 0.87 \times 0.87 = 0.7569\)
3. \(P(\text{Luxury and Breaks Down}) = 0.08 \times 0.92 = 0.0736\)
4. \(P(\text{Luxury and Does Not Break Down}) = 0.92 \times 0.92 = 0.8464\)
5. \(P(\text{Budget and Breaks Down}) = 0.40 \times 0.60 = 0.24\)
6. \(P(\text{Budget and Does Not Break Down}) = 0.60 \times 0.60 = 0.36\)
Step-by-step explanation:
The multiplication principle allows us to calculate the probabilities of independent events occurring together. For small cars, the probability of breaking down is 0.13, so the probability of not breaking down is \(1 - 0.13 = 0.87\). Therefore, the probability of a small car both breaking down and not breaking down is calculated by multiplying these individual probabilities, yielding \(0.13 \times 0.87 = 0.1131\) and \(0.87 \times 0.87 = 0.7569\), respectively.
Similarly, for luxury sedans, the probability of breaking down is 0.08, and the probability of not breaking down is \(1 - 0.08 = 0.92\). The probabilities of a luxury sedan breaking down and not breaking down are \(0.08 \times 0.92 = 0.0736\) and \(0.92 \times 0.92 = 0.8464\), respectively.
For budget vehicles, the probability of breaking down is 0.40, and the probability of not breaking down is \(1 - 0.40 = 0.60\). The probabilities of a budget vehicle breaking down and not breaking down are \(0.40 \times 0.60 = 0.24\) and \(0.60 \times 0.60 = 0.36\), respectively.